Latest LSAT-Logical-Reasoning Practice Tests with Actual Questions

Get Complete pool of questions with Premium PDF and Test Engine

Exam Code : LSAT-Logical-Reasoning
Exam Name : Section One Logical Reasoning
Vendor Name :
"Admission-Tests"

Download Full Version of LSAT-Logical-Reasoning

---

LSAT-Logical-Reasoning Dumps LSAT-Logical-Reasoning Braindumps

LSAT-Logical-Reasoning Real Questions LSAT-Logical-Reasoning Practice Test LSAT-Logical-Reasoning Actual Questions

Admission-Tests

LSAT-Logical-Reasoning

Section One Logical Reasoning

https://killexams.com/pass4sure/exam-detail/LSAT-Logical-Reasoning

Question #401

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected.

Which one of the following could be the selection of stones?

1. F, G, H, M, X, Y

2. F, G, J, K, M, W

3. F, G, J, K, W, X

4. G, H, J, X, Y, Z

5. G, H, K, W, X, Z

Answer: D

Even if you were blown away by this games rules, this is a point worth getting, and worth getting quickly. Rule 1s requirement of 2 topazes minimum is violated by

B.. Rule 2s 2 sapphires : 1 ruby ratio is violated by C., which gives us 2 : 2 : 2. Rule 3 is violated by E., which gives us W, H, and Z all at once. And Rule 4 is violated by A., which gives us M without W. D. must be correct sight unseen, and perhaps finding it, and then analyzing it, can provide us with some needed insight into the game and the heart to keep going with it.

Question #402

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected. Which one of the following must be true?

1. G is selected.

2. J is selected.

3. X is selected.

4. Of at least one of the three types of stones,exactly one stone is selected.

5. Of at least one of the three types of stones,exactly three stones are selected.

Answer: E

Those who worked out the number options we laid out above had no trouble with this one. No matter how you slice it, at least one stone typeand possibly two are represented by exactly 3 stones. And even if you didnt work out every possibility, simply seeing that 2 : 2 : 2 was an impossible ratio(because of Rule 2) might have led you to suspect that E. was a true statement. A., B., and C. are far from necessarily truethere are lots of possibilities in which G, J, and X respectively are not present. And the possibility of choosing, say, 3 sapphires + 3 topazes means that D. need not be true either.

Question #403

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare

rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected.

If Z is selected, which one of the following could be true?

1. All three of the sapphires are selected.

2. Both J and M are selected.

3. Both K and M are selected.

4. None of the rubies is selected.

5. None of the sapphires is selected.

Answer: E

Write out your roster, circle Z on it, and realize that thats a trigger for rejecting W (Rule 3s contrapositive) and thus for rejecting M (Rule 4s contrapositive). Thats all we need. With sapphire M gone, clearly A.,B., and C. are impossible. And if D. were trueno rubiesour remaining 2 sapphires and maximum of 3 topazes would leave us short of our desired total of 6. So E. is possible by default. Indeed, all three rubies plus topazes X, Y, Z would constitute an acceptable set of 6.

Question #404

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected.

If exactly two rubies are selected, which one of the following must be true?

1. H is selected.

2. J is selected.

3. Z is selected.

4. Exactly one sapphire is selected.

5. Exactly two topazes are selected

Answer: D

This is sheer arithmetic. If we choose exactly 2 rubies, we cannot choose 2 topazesremember, 2: 2 : 2 is forbiddenso we need exactly 3 topazes (and have proved thatE.is impossible, incidentally).And 2 rubies + 3 topazes only = 5 stones, so there will be exactly 1 sapphire chosen, choice D.What that sapphire is, is unclear; it could be J, as B. suggests, but need not. And A. and C. are much more certain as to the identity of particular stones than we can possibly be, under this questions circumstances.

Question #405

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected. Which one of the following must be true?

1. The selection of stones includes at least one ruby.

2. The selection of stones includes at most two rubies.

3. The selection of stones includes either F or Z, or both.

4. The selection of stones includes either X or Y, or both.

5. The selection of stones includes either X or Z, or both.

Answer: D

We have deduced that at least two topazes must be chosen at all times. And which two? Hard to say; but since we can never choose W and Z together (Rule 3), we will always need to choose at least one of the remaining topazes. Thats all that D. is saying. Our work in Step 4, above, demonstrates that neither A. nor B. need be true. Contrary to both A. and B., we could choose no rubies at all (if we used 3 sapphires and 3 topazes). The remaining choices may require a little trial and error, but the selection of, for instance, "G,J,K,M,W,Y" proves that neither C. nor E. need be true.

Question #406

From among ten stones, a jeweler will select six, one for each of six rings. Of the stones, threeF, G, and Hare rubies; threeJ, K, and Mare sapphires; and fourW, X, Y, and Zare topazes. The selection of stones must meet the following restrictions:

At least two of the topazes are selected.

If exactly two of the sapphires are selected, exactly one of the rubies is selected. If W is selected, neither H nor Z is selected.

If M is selected, W is also selected.

If J and M are the only sapphires selected, which one of the following could be true?

1. F and G are both selected.

2. F and X are both selected.

3. G and H are both selected.

4. G and K are both selected.

5. Y and Z are both selected.

Answer: B

Interestinglyif frustratinglythis last question proves to be one of the most concrete, and hence one of the easiest. We hope that you didnt get bogged down on some of the earlier ones and miss out onthis one. In your roster, select J and M, and cross out K, in line with the question stems if. Rule 4 requires that you select

W, and Rule 3 requires that you cross out H and Z. At the same time, Rule 2 (we use it at last!) kicks inthere will be exactly 1 ruby chosen, and hence 3 sapphires. And with Z gone, those 3sapphires are W, X, and Y. So: J, M, W, X, and Y are definitely chosen, and the final stone will be a ruby, either F or G.

1. is therefore the only possibility among the choices. A. would stick us with a total of 7 stones. And each of the remaining choices mentions a stone that we have definitively rejected: H in C., K in D.,and Z in E.

   
   

   Question #407

   
   

   There are exactly ten stores and no other buildings on Oak Street. On the north side of the street, from west to east, are stores 1, 3, 5, 7, and 9; on the south side of the street, also from west to east, are stores 2, 4, 6, 8, and 10. The stores on the north side are located directly across the street from those on the south side, facing each other in pairs, as follows: 1 and 2; 3 and 4; 5 and 6; 7 and 8; 9 and 10. Each store is decorated with lights in exactly one of the following colors: green, red, and yellow. The stores have been decorated with lights according to the following conditions:

   No store is decorated with lights of the same color as those of any store adjacent to it.

   No store is decorated with lights of the same color as those of the store directly across the street from it. Yellow lights decorate exactly one store on each side of the street.

   Red lights decorate store 4. Yellow lights decorate store 5.

   Which one of the following could be an accurate list of the colors of the lights that decorate stores 2, 4, 6, 8, and 10, respectively?

   
   

   1. green, red, green, red, green

   2. green, red, green, yellow, red

   3. green, red, yellow, red, green

   4. yellow, green, red, green, red

   5. yellow, red, green, red, yellow

Answer: B

The right answer is an acceptable matching for the five south side streets, and weve got most of that worked out. Stores 4 and 6 are red and green respectively, so C. and D. can be crossed out. There is one and only one yellow light, so A. with no yellows and E. with two are both eliminated. B. is all thats left.

Question #408

There are exactly ten stores and no other buildings on Oak Street. On the north side of the street, from west to east, are stores 1, 3, 5, 7, and 9; on the south side of the street, also from west to east, are stores 2, 4, 6, 8, and 10. The stores on the north side are located directly across the street from those on the south side, facing each other in pairs, as follows: 1 and 2; 3 and 4; 5 and 6; 7 and 8; 9 and 10. Each store is decorated with lights in exactly one of the following colors: green, red, and yellow. The stores have been decorated with lights according to the following conditions:

No store is decorated with lights of the same color as those of any store adjacent to it.

No store is decorated with lights of the same color as those of the store directly across the street from it. Yellow lights decorate exactly one store on each side of the street.

Red lights decorate store 4. Yellow lights decorate store 5.

If green lights decorate store 7, then each of the following statements could be false EXCEPT:

1. Green lights decorate store 2.

2. Green lights decorate store 10.

3. Red lights decorate store 8.

4. Red lights decorate store 9.

5. Yellow lights decorate store 2.

Answer: D

A mini-sketch for this question should recopy what we know and add "G" to store 7. Store 9, which we knew was "G/R," is now definitively "R." And that’s it; we cannot confirm anything more on the south side. But thats enough: store 9 has to be red, so D. cannot be false.

Of A. and E., exactly one is truestore 2 is green or yellowbut we dont know which. Store 8could be red or yellow, so C. can be false. And store 10 remains uncertain, so B.can be false too.

Question #409

There are exactly ten stores and no other buildings on Oak Street. On the north side of the street, from west to east, are stores 1, 3, 5, 7, and 9; on the south side of the street, also from west to east, are stores 2, 4, 6, 8, and 10. The stores on the north side are located directly across the street from those on the south side, facing each other in pairs, as follows: 1 and 2; 3 and 4; 5 and 6; 7 and 8; 9 and 10. Each store is decorated with lights in exactly one of the following colors: green, red, and yellow. The stores have been decorated with lights according to the following conditions:

No store is decorated with lights of the same color as those of any store adjacent to it.

No store is decorated with lights of the same color as those of the store directly across the street from it. Yellow lights decorate exactly one store on each side of the street.

Red lights decorate store 4. Yellow lights decorate store 5.

Which one of the following statements must be true?

1. Green lights decorate store 10.

2. Red lights decorate store 1.

3. Red lights decorate store 8.

4. Yellow lights decorate store 8.

5. Yellow lights decorate store 10.

Answer: B

This one is a slam-dunk. We have deduced that store 1 has red lights. Question #410

There are exactly ten stores and no other buildings on Oak Street. On the north side of the street, from west to east, are stores 1, 3, 5, 7, and 9; on the south side of the street, also from west to east, are stores 2, 4, 6, 8, and 10. The stores on the north side are located directly across the street from those on the south side, facing each other in pairs, as follows: 1 and 2; 3 and 4; 5 and 6; 7 and 8; 9 and 10. Each store is decorated with lights in exactly one of the following colors: green, red, and yellow. The stores have been decorated with lights according to the following conditions:

No store is decorated with lights of the same color as those of any store adjacent to it.

No store is decorated with lights of the same color as those of the store directly across the street from it. Yellow lights decorate exactly one store on each side of the street.

Red lights decorate store 4. Yellow lights decorate store 5.

If green lights decorate five stores on the street, then which one of the following statements must be true?

1. Green lights decorate store 9.

2. Red lights decorate store 2.

3. Red lights decorate store 7.

4. Red lights decorate store 10.

5. Yellow lights decorate store 8.

Answer: E

The trick here is to figure out which of the ten stores are the five that will have green lights. On the north side, with store 3 always green, we will have to have a green light in store 7 or 9. (Remember, adjacent greens are prohibited.) It may be smart to draw out both possibilities. And happily the south side is determinable.

On the south side, we need three more greens, and clearly theyll have to be stores 2, 6, and10. And with store 4 always red, the requisite (Rule 3) yellow will go to store 8. So here are the two options:

User: Zakhar***** The practice tests provided by Killexams.com helped me achieve a score of 86% on the LSAT-LOGICAL-REASONING exam. I was pleased to see that around 90% of the questions were similar to the material provided by Killexams.com. I had difficulty with the complex themes, but the material provided helped me overcome those troubles.

User: Abigail***** I scored 92% in my lsat-logical-reasoning exam today, and I credit my success to killexams.com. Their questions are relevant, and the data is accurate. This is the first time I used their services, but I am confident that I will return to this website for all of my lsat-logical-reasoning certification exams. Thank you, killexams.com, for being my primary preparation aid.

User: Joaquín***** Due to my limited time, I searched for a smooth way out before the LSAT-LOGICAL-REASONING exam. I stumbled upon killexams.com question and answers, which made my day. The quick and pointed answers to all the likely questions helped me grasp the topics in a short time, and I was pleased to secure accurate marks in the exam. The materials were also easy to memorize, and I am inspired and satisfied with my result.

User: Emma***** I had a great experience using the instruction provided by killexams.com for my preparation of the lsat-logical-reasoning exam. The platform was very helpful and provided me with the necessary tools to achieve a high score. The engaging and efficient way in which the materials were presented made my learning experience simpler and more enjoyable. With the aid of killexams.com, I was able to grow both personally and professionally.

User: Tiahna***** Thanks to Killexams.com, I was able to request and practice for a week before taking the lsat-logical-reasoning exam, which I passed with an impressive 89% marks. This is what a great exam arrangement should look like for everyone. The website superb collection of exam association practice tests and materials made it possible for me to become a lsat-logical-reasoning certified companion. The questions are valid, and the exam simulator works efficiently without any problems. I highly recommend Killexams.com Questions and Answers.

---